Atrisini vienādojumu log22 (2x) + log2 = 23
Atbilde ( 1 + log2x)2 + 2 - log2x – 23 = 0 log2x = t t2 + 2t + 1 + 2 – t -23 = 0 t2 + t – 20 = 0 t1 = 4; t2 = -5 log2x = 4; log2x = -5 x1 = 16; x2 =